Suite • opensavvy.prepared.suite • map

map

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fun <I, O> Prepared<I>.map(name: String, block: (I) -> O): Prepared<O>

Creates a new Prepared which is the result of calling block on the input prepared value.

Parameters

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fun <I, O> PreparedProvider<I>.map(block: (I) -> O): PreparedProvider<O>

Creates a new PreparedProvider which is the result of calling block on the input prepared provider.